The Unit Circle

The unit circle is a circle of radius 1 that we can use to pull together Pythagoras and trigonometry. The unit circle has the equation:

(1)   \begin{equation*}  1 = x^{2} + y^{2} \end{equation*}

This looks like this:

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If we project a line from the origin to a point (x,y) on the unit circle we get:

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If we construct a triangle from this line to the x and y axis, we can use the trigonometric functions to find the values for the coordinates of the point on the unit circle. Remembering that the adjacent is related to the hypotenuse via:

(2)   \begin{equation*}  \cos(\theta) = \frac{\text{adjacent}}{\text{hypotenuse}} \end{equation*}

With the hypotenuse having a value of 1 we can see that:

(3)   \begin{equation*}  \cos(\theta) = \text{adjacent} \end{equation*}

So that gives us x = \cos(\theta). We can do the same for the opposite, using the sine of \theta

(4)   \begin{equation*}  \sin(\theta) = \frac{\text{opposite}}{\text{hypotenuse}} \end{equation*}

Again the hypotenuse is 1, so we have:

(5)   \begin{equation*}  \sin(\theta) = \text{opposite} \end{equation*}

Which gives us y = \sin(\theta).

We can now combine those results with Pythagoras’s theorem to see that any line from the origin at (0,0) to a point (x,y) on the unit circle gives:

(6)   \begin{equation*}  1 = \cos^{2}(\theta) + \sin^{2}(\theta) \end{equation*}

So on a diagram we have the following:

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From the diagram we can see that the triangle formed when we project a line from the origin to a point on the circle will give side lengths related to the trigonometric ratios. The base or adjacent is \cos(\theta) and the side or opposite is \sin(\theta). So the unit circle ties together Pythagoras and the trigonometric ratios for \sin and \cos. Any point on the unit circle has the coordinates (\cos(\theta),\sin(\theta)).

 

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